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15x^2-85x+100=0
a = 15; b = -85; c = +100;
Δ = b2-4ac
Δ = -852-4·15·100
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-85)-35}{2*15}=\frac{50}{30} =1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-85)+35}{2*15}=\frac{120}{30} =4 $
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